Java: Sort three numbers

package chapter6_6_5;
import java.util.Scanner;
/**
 *
 * @author Siavash Bakhshi
 */
public class Chapter6_6_5 {

    /**
     * @param args the command line arguments
     */
    /** Main method */
    public static void main(String[] args) {
        double num1;
        double num2;
        double num3;
        // Create a Scanner
        Scanner input = new Scanner(System.in);
        System.out.print("Please enter 1st Number: ");
        num1 = input.nextDouble();
        System.out.print("Please enter 2nd Number: ");
        num2 = input.nextDouble();
        System.out.print("Please enter 3rd Number: ");
        num3 = input.nextDouble();
        displaySortedNumbers(num1, num2, num3);
    }
    
    /** Return the max between two numbers */
    public static void displaySortedNumbers(double num1, double num2, double num3) {
         double max=0;
         double med=0;
         double min=0;
        //get Max
        if ((num1 > num2 && num1 > num3))
        {
            max = num1;
            if(num2 > num3)
            {
                med = num2;
                min = num3;
            }
            else
            {
                med = num3;
                min = num2;
            }
        }
        else if ((num2 > num1 && num2 > num3))
        {
            max = num2;
            if(num3 > num1)
            {
                med = num3;
                min = num1;
            }
            else
            {
                med = num1;
                min = num3;
            }            
        }
        else if ((num3 > num1 && num3 > num2))
        {
            max = num3;
            if(num1 > num2)
            {
                med = num1;
                min = num2;
            }
            else
            {
                med = num2;
                min = num1;
            }            
        }
        else
        {
            System.out.println("ERROR!");
        }
        System.out.println("Numbers in increasing order:  " + min + " , " + med + " , " + max);
            
    }
    
}